Question:

The weight of $AgCl$ precipitated when a solution containing 5.85 g of $NaCl$ is added to a solution containing 3.4 g of $ {AgNO_3}$ is

Updated On: Jun 23, 2023
  • 28 g
  • 9.25 g
  • 2.87 g
  • 58 g
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The Correct Option is C

Solution and Explanation

$ {AgNO_3 + NaCl ? AgCl + NaNO_3}$ No. of moles of $ {AgNO_3 = \frac{3.4}{170} = 0.02}$ No. of moles of $ {NaCl = \frac{5.85}{58.5} = 0.1}$ Limiting reagent =$ { AgNO_3}$ $\because$ 1 mole of $ {AgNO_3}$ produces 1 mole of $ {AgCl}$ $\therefore $ 0.02 mole of $ {AgNO_3}$ will produce 0.02 mole of $ {AgCl}$ Weight of $ {AgCl}$ produced = $0.02 \times 143.5$ = $2.870 \, g$
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Concepts Used:

Solutions

A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.

For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.

Types of Solutions:

The solutions can be classified into three types:

  • Solid Solutions - In these solutions, the solvent is in a Solid-state.
  • Liquid Solutions- In these solutions, the solvent is in a Liquid state.
  • Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.

On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:

  1. Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
  2. Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
  3. Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.