Step 1: Explanation of the Phenomenon
When high
energy electrons strike a metal target, the energy from the electrons is transferred to the metal atoms. This energy causes the ejection of inner shell electrons in the atoms of the metal, and when electrons from higher energy levels fall back to fill these vacancies, they emit energy in the form of electromagnetic radiation.
Step 2: Identifying the Type of Radiation
The energy released in this process is typically in the form of X rays, which have a much higher energy than visible light and are part of the electromagnetic spectrum.
Other radiation types, such as microwaves, infrared rays, and radio waves, have lower energy compared to Xnrays and are not produced in this phenomenon.
Final Answer: The correct answer is \( X rays .\)
For the circuit shown in the figure, the active power supplied by the source is ________ W (rounded off to one decimal place).
A signal $V_M = 5\sin(\pi t/3) V$ is applied to the circuit consisting of a switch S and capacitor $C = 0.1 \mu F$, as shown in the figure. The output $V_x$ of the circuit is fed to an ADC having an input impedance consisting of a $10 M\Omega$ resistance in parallel with a $0.1 \mu F$ capacitor. If S is opened at $t = 0.5 s$, the value of $V_x$ at $t = 1.5 s$ will be ________ V (rounded off to two decimal places).
Note: Assume all components are ideal.
In the circuit shown, the switch is opened at $t = 0$ s. The current $i(t)$ at $t = 2$ ms is ________ mA (rounded off to two decimal places).
In the circuit shown, the galvanometer (G) has an internal resistance of $100 \Omega$. The galvanometer current $I_G$ is ________ $\mu A$ (rounded off to the nearest integer).