For a bulb of rating 4V, 6W, we can calculate the resistance using the formula: \[ P = \frac{V^2}{R} \] Thus, \( R = \frac{V^2}{P} = \frac{4^2}{6} = \frac{16}{6} \approx 2.67 \, \Omega \). Now, to operate safely with a 240V mains supply, the total resistance in the series connection must be: \[ R_{{total}} = \frac{V_{{total}}^2}{P_{{total}}} \] For total power 6W per bulb, and for the total power at 240V, the number of bulbs required can be calculated to be 40.
Thus, the correct answer is option (b).
Two p-n junction diodes \(D_1\) and \(D_2\) are connected as shown in the figure. \(A\) and \(B\) are input signals and \(C\) is the output. The given circuit will function as a _______. 
In the circuit with ideal devices, the power MOSFET is operated with a duty cycle of 0.4 in a switching cycle with \( I = 10 \, {A} \) and \( V = 15 \, {V} \). The power delivered by the current source, in W, is: \[ {(round off to the nearest integer).} \] 
The op-amps in the following circuit are ideal. The voltage gain of the circuit is __________ (round off to the nearest integer). 
The switch (S) closes at \( t = 0 \) sec. The time, in sec, the capacitor takes to charge to 50 V is ___________ (round off to one decimal place).
Read the following sources of loan carefully and choose the correct option related to formal sources of credit:
(i) Commercial Bank
(ii) Landlords
(iii) Government
(iv) Money Lende