Question:

The vector equation of a line passing through the point \( (1, -1, 0) \) and parallel to the \( y \)-axis is:

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Vector equations of lines require a point and a direction vector.
Updated On: Feb 19, 2025
  • \[ \mathbf{r} = \hat{i} - \hat{j} + \lambda (\hat{i} - \hat{j}) \]
  • \[ \mathbf{r} = \hat{i} - \hat{j} + \lambda \hat{j} \]
  • \[ \mathbf{r} = \hat{i} - \hat{j} + \lambda \hat{k} \]
  • \[ \mathbf{r} = \lambda \hat{j} \]
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The Correct Option is B

Solution and Explanation

Step 1: Identify the direction vector
The direction vector is along the \( y \)-axis, so it is \( \hat{j} \).

Step 2: Write the line equation
The vector equation of a line passing through \( (1, -1, 0) \) is: \[ \mathbf{r} = \mathbf{r}_0 + \lambda \mathbf{d}, \] where \( \mathbf{r}_0 = \hat{i} - \hat{j} \) and \( \mathbf{d} = \hat{j} \).

Step 3: Substitute values
\[ \mathbf{r} = (\hat{i} - \hat{j}) + \lambda \hat{j} = \hat{i} - \hat{j} + \lambda \hat{j}. \]
Step 4: Verify the options
The correct equation is: \[ \mathbf{r} = \hat{i} - \hat{j} + \lambda \hat{j} \] which matches option (B).
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