The materials can be categorized as conductors, insulators, and semiconductors based on their conductivity values at 298.15 K.
Conductors generally have conductivities on the order of \(10^2\) to \(10^6 \, \text{S m}^{-1}\).
Insulators have very low conductivities, typically around \(10^{-10}\) to \(10^{-8} \, \text{S m}^{-1}\).
Semiconductors have conductivities ranging from \(10^{-4}\) to \(10 \, \text{S m}^{-1}\).
Given values:
\[ 2.1 \times 10^3, \, 1.2 \times 10^3, \, 3.91, \, 1.5 \times 10^{-2}, \, 1 \times 10^{-7}, \, 1.0 \times 10^3 \]
Classifying each:
Therefore, the number of conductors is: 4.
If the molar conductivity ($\Lambda_m$) of a 0.050 mol $L^{–1}$ solution of a monobasic weak acid is 90 S $cm^{2} mol^{–1}$, its extent (degree) of dissociation will be:
[Assume: $\Lambda^0$ = 349.6 S $cm^{2} mol^{–1}$ and $\Lambda^0_{\text{acid}}$ = 50.4 S$ cm^{2} mol^{–1}$]
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: