The conductivity of a material indicates its ability to conduct electricity. Materials with high conductivity are categorized as conductors. For this analysis, a standard threshold is needed: materials with conductivities significantly greater than \( 1 \, \text{S m}^{-1} \) are typically considered conductors. Let's evaluate each given material based on this criteria.
Counting the number of materials with conductivity greater than \( 1 \, \text{S m}^{-1} \), we find 4 conductors:
The number of conductors is thus 4, which matches the expected range (4).
The materials can be categorized as conductors, insulators, and semiconductors based on their conductivity values at 298.15 K.
Conductors generally have conductivities on the order of \(10^2\) to \(10^6 \, \text{S m}^{-1}\).
Insulators have very low conductivities, typically around \(10^{-10}\) to \(10^{-8} \, \text{S m}^{-1}\).
Semiconductors have conductivities ranging from \(10^{-4}\) to \(10 \, \text{S m}^{-1}\).
Given values:
\[ 2.1 \times 10^3, \, 1.2 \times 10^3, \, 3.91, \, 1.5 \times 10^{-2}, \, 1 \times 10^{-7}, \, 1.0 \times 10^3 \]
Classifying each:
Therefore, the number of conductors is: 4.

Consider the above electrochemical cell where a metal electrode (M) is undergoing redox reaction by forming $M^+$ ($M \to M^+ + e^-$). The cation $M^+$ is present in two different concentrations $c_1$ and $c_2$ as shown above. Which of the following statement is correct for generating a positive cell potential?
MX is a sparingly soluble salt that follows the given solubility equilibrium at 298 K.
MX(s) $\rightleftharpoons M^{+(aq) }+ X^{-}(aq)$; $K_{sp} = 10^{-10}$
If the standard reduction potential for $M^{+}(aq) + e^{-} \rightarrow M(s)$ is $(E^{\circ}_{M^{+}/M}) = 0.79$ V, then the value of the standard reduction potential for the metal/metal insoluble salt electrode $E^{\circ}_{X^{-}/MX(s)/M}$ is ____________ mV. (nearest integer)
[Given : $\frac{2.303 RT}{F} = 0.059$ V]


A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T. If the resistance of the total circuit is 2 \(\Omega\) then the force needed to move the rod towards right with constant speed (v) of 1.5 m/s is _____ N.