Question:
The value of the sum of 10 term of the series
\(S_{10}=\frac{1}{2^2-1}+\frac{1}{4^2-1}+\frac{1}{6^2-1}+...\)
The value of the sum of 10 term of the series
\(S_{10}=\frac{1}{2^2-1}+\frac{1}{4^2-1}+\frac{1}{6^2-1}+...\)
\(S_{10}=\frac{1}{2^2-1}+\frac{1}{4^2-1}+\frac{1}{6^2-1}+...\)
Updated On: Sep 12, 2024
- \(\frac{11}{21}\)
- \(\frac{9}{10}\)
- \(\frac{21}{10}\)
- \(\frac{10}{21}\)
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The Correct Option is D
Solution and Explanation
The correct option is (D):\(\frac{10}{21}\).
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