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if f z 1 z 2 3z 2 is expanded in the region z 1 th
Question:
If
\(f(z)=\frac{1}{z^2-3z+2}\)
is expanded in the region |z|<1, then
CUET (PG) - 2023
CUET (PG)
Updated On:
Mar 12, 2025
\(f(z)=\frac{1}{2}+\frac{3z}{4}+\frac{7}{8}z^2+\frac{15}{16}z^3+.......\)
\(f(z)=\frac{1}{2}+\frac{4}{3}z+\frac{8}{7}z^2+\frac{16}{15}z^3+.......\)
\(f(z)=\frac{1}{2}+\frac{3z}{4}+\frac{7}{9}z^2+\frac{15}{19}z^3+.......\)
\(f(z)=\frac{1}{2}+\frac{3z}{4}+\frac{6}{7}z^2+\frac{15}{11}z^3+.......\)
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The Correct Option is
A
Solution and Explanation
The correct answer is(A):
\(f(z)=\frac{1}{2}+\frac{3z}{4}+\frac{7}{8}z^2+\frac{15}{16}z^3+.......\)
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