Question:
The value of the limit
\(lim _{n→∞}(\frac{1^4+2^4+…+n^4}{n^5}+\frac{1}{√n}(\frac{1}{\sqrt{n+1}}+\frac{1}{\sqrt{n+2}}+...+\frac{1}{\sqrt{4n}}))\)
is equal to___(Rounded off two decimal places)
The value of the limit
\(lim _{n→∞}(\frac{1^4+2^4+…+n^4}{n^5}+\frac{1}{√n}(\frac{1}{\sqrt{n+1}}+\frac{1}{\sqrt{n+2}}+...+\frac{1}{\sqrt{4n}}))\)
is equal to___(Rounded off two decimal places)
\(lim _{n→∞}(\frac{1^4+2^4+…+n^4}{n^5}+\frac{1}{√n}(\frac{1}{\sqrt{n+1}}+\frac{1}{\sqrt{n+2}}+...+\frac{1}{\sqrt{4n}}))\)
is equal to___(Rounded off two decimal places)
Updated On: Oct 1, 2024
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Correct Answer: 2.19 - 2.21
Solution and Explanation
The correct answer is: 2.19 to 2.21 (approx)
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