Question:
The value of the integral \(\int\frac{1-\sin x}{\cos^2 x}dx\) is :
The value of the integral \(\int\frac{1-\sin x}{\cos^2 x}dx\) is :
Updated On: Jun 13, 2024
- secx - tanx + C, Where C is an arbitrary constant.
- tanx - secx + C, Where C is an arbitrary constant.
- secx tanx + C, Where C is an arbitrary constant.
- tanx + secx + C, Where C is an arbitrary constant.
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The Correct Option is B
Solution and Explanation
The correct option is (B) :tanx - secx + C, Where C is an arbitrary constant.
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