Question:
The value of the determinant \(\begin{vmatrix}cos^2θ&cosθsinθ&0 \\-sinθ&cosθ&0 \\ 0&0&1 \end{vmatrix}\) is equal to
The value of the determinant \(\begin{vmatrix}cos^2θ&cosθsinθ&0 \\-sinθ&cosθ&0 \\ 0&0&1 \end{vmatrix}\) is equal to
Updated On: Apr 19, 2024
- 1
- cos θ
- cos 2θ
- cos θ-sin θ
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The Correct Option is B
Solution and Explanation
The correct option is(B):cos θ
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