The value of
$$
\lim_{x \to 0} (1 + 2x)^{1/x}
$$
is
Show Hint
When you encounter a limit like \( (1 + u)^{1/u} \), recognize it as a form of the exponential limit that tends to \( e^2 \) if the expression inside the parentheses is \( 2x \).
The limit in the question is of the form \( (1 + \text{something small})^{\text{something large}} \), which is a standard limit that approaches \( e^2 \) when simplified.
To evaluate the limit, we use the following approximation:
\[
\lim_{x \to 0} (1 + 2x)^{1/x} = e^{\lim_{x \to 0} \frac{\ln(1 + 2x)}{x}}
\]
Using the approximation \( \ln(1 + u) \approx u \) for small \( u \), we get:
\[
\lim_{x \to 0} \frac{\ln(1 + 2x)}{x} = \lim_{x \to 0} \frac{2x}{x} = 2
\]
Thus, the limit is:
\[
e^2
\]
Therefore, the correct answer is 2. \( e^2 \).