Question:
The value of \(\displaystyle\sum_{k=5}^{36}\frac{1}{k^2-k}\) is equal to
The value of \(\displaystyle\sum_{k=5}^{36}\frac{1}{k^2-k}\) is equal to
Updated On: Jun 10, 2024
- \(\frac{7}{36}\)
- \(\frac{1}{9}\)
- \(\frac{2}{9}\)
- \(\frac{1}{12}\)
- \(\frac{5}{36}\)
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The Correct Option is C
Solution and Explanation
The correct option is (C): \(\frac{2}{9}\)
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