\(0\)
\(1\)
\(2\)
\(4\)
\(6\)
Given:
Step 1: Rewrite trigonometric functions in terms of sine and cosine: \[ \csc 20° = \frac{1}{\sin 20°}, \quad \tan 60° = \frac{\sin 60°}{\cos 60°}, \quad \sec 20° = \frac{1}{\cos 20°} \]
Step 2: Substitute known values: \[ \sin 60° = \frac{\sqrt{3}}{2}, \quad \cos 60° = \frac{1}{2} \] \[ \tan 60° = \frac{\frac{\sqrt{3}}{2}}{\frac{1}{2}} = \sqrt{3} \]
Step 3: Rewrite the original expression: \[ \frac{1}{\sin 20°} \cdot \sqrt{3} - \frac{1}{\cos 20°} \] \[ = \frac{\sqrt{3}}{\sin 20°} - \frac{1}{\cos 20°} \]
Step 4: Combine the terms: \[ = \frac{\sqrt{3} \cos 20° - \sin 20°}{\sin 20° \cos 20°} \]
Step 5: Recognize the numerator as a trigonometric identity: \[ \sqrt{3} \cos 20° - \sin 20° = 2 \sin (60° - 20°) = 2 \sin 40° \]
Step 6: Simplify the denominator using double-angle identity: \[ \sin 20° \cos 20° = \frac{1}{2} \sin 40° \]
Step 7: Final simplification: \[ \frac{2 \sin 40°}{\frac{1}{2} \sin 40°} = 4 \]
The correct answer is (D) 4.
\(cosec20.tan60-sec20\)
\(=\dfrac{1}{sin20}×\dfrac{sin60}{cos60}-\dfrac{1}{cos20}\)
\(=\dfrac{sin60.cos20-cos60.sin20}{sin20.cos60.cos20}\)
\(=\dfrac{sin(60-20)}{\dfrac{1}{2}.sin20.cos20}\)
\(=\dfrac{2.sin40}{sin20.cos20}\)
\(=\dfrac{2sin2(20)}{sin20.cos20}\)
\(=\dfrac{4sin20.cos20}{sin20.cos20}\)
\(=4\)
The given graph illustrates:
Trigonometry is a branch of mathematics that deals with the relationships between the sides and angles of triangles. It has many practical applications in various fields, including science, engineering, architecture, and navigation. Here are some examples:
Read Also: Some Applications of Trigonometry
Overall, trigonometry is a versatile tool that has many practical applications in various fields and continues to be an essential part of modern mathematics.