To solve the expression \(5^{\frac{1}{4}}\times(125)^{0.25}\), we first need to simplify each term:
\(5^{\frac{1}{4}}\) is evaluating the 4th root of 5.
Similarly, \(125^{0.25}\) means finding the 4th root of 125.
Now, let's simplify \(125^{0.25}\):
Notice that \(125 = 5^3\), so we can rewrite the expression as \((5^3)^{0.25}\).
Using the power of a power property, \((a^m)^n = a^{m \cdot n}\), we have:
\((5^3)^{0.25} = 5^{3 \cdot 0.25} = 5^{0.75}\).
Now our original expression becomes:
\(5^{\frac{1}{4}} \times 5^{0.75}\).
We can now apply the property of exponents \(a^m \times a^n = a^{m+n}\):
\(5^{\frac{1}{4} + 0.75} = 5^{\frac{1}{4} + \frac{3}{4}}\).
Simplifying the exponents: \(\frac{1}{4} + \frac{3}{4} = 1\).
Thus, the expression simplifies to \(5^1 = 5\).
The value is 5.