Class Interval | 50-70 | 70-90 | 90-110 | 110-130 | 130-150 | 150-170 |
---|---|---|---|---|---|---|
Number of Students | 15 | 21 | 32 | 19 | 8 | 5 |
The cumulative frequencies are:
50-70: 15 50-90: 15+21 = 36
50-110: 36+32 = 68
50-130: 68+19 = 87
50-150: 87+8 = 95
50-170: 95+5 = 100
The total number of observations is 100.
The median is the value such that half the observations are below it and half are above it.
Since there are 100 observations, the median will be the average of the 50th and 51st observations.
The cumulative frequency tells us the number of observations below the upper limit of each class.
The 50th and 51st observations will lie in the class interval 90-110 since the cumulative frequency of the 50-90 class is 36, and the cumulative frequency of the 50-110 class is 68.
So the median class is 90-110. The upper limit of the median class is 110.
The following data shows the number of family members living in different bungalows of a locality:
Number of Members | 0−2 | 2−4 | 4−6 | 6−8 | 8−10 | Total |
---|---|---|---|---|---|---|
Number of Bungalows | 10 | p | 60 | q | 5 | 120 |
If the median number of members is found to be 5, find the values of p and q.
The population of lions was noted in different regions across the world in the following table:
Number of lions | Number of regions |
---|---|
0–100 | 2 |
100–200 | 5 |
200–300 | 9 |
300–400 | 12 |
400–500 | x |
500–600 | 20 |
600–700 | 15 |
700–800 | 10 |
800–900 | y |
900–1000 | 2 |
Total | 100 |
If the median of the given data is 525, find the values of x and y.