In a two-dimensional square lattice, the unit cell is a square with side length a. The four grey circles inside the unit cell have a radius r. The total area occupied by the grey circles is the combined area of the four circles.
The area of one circle is given by the formula:
Acircle = \( \pi r^2 \)
Since there are four circles in the unit cell, the total area occupied by the circles is:
Atotal = 4 · \( \pi r^2 \)
The area of the square unit cell is:
Aunitcell = \( a^2 \)
Since the distance between the centers of adjacent circles is a, the relationship between a and r is:
a = 2r
Therefore, the area occupied by the grey circles as a percentage of the total unit cell area is:
Percentage occupied = \( \frac{A_{total}}{A_{unitcell}} \) × 100 = \( \frac{4 \cdot \pi r^2}{(2r)^2} \) × 100
Simplifying this:
Percentage occupied = \( \frac{4 \cdot \pi r^2}{4r^2} \) × 100 = \( \pi \) × 100 ≈ 77%
Thus, the percentage area occupied by the grey circles is 77%.
Dry ice is:
Which among the following is a supercooled liquid?