The Rayleigh-Jeans theory of cavity radiation assumes that the standing waves of all allowed frequencies in the cavity have the same average energy. This assumption leads to an overestimation of the energy at high frequencies, a phenomenon known as the ultraviolet catastrophe.
The assumption in option (A) implies that every frequency mode contributes equally to the radiation energy. At high frequencies, this leads to the prediction of infinite energy, resulting in the ultraviolet catastrophe.
This assumption was later corrected by Planck’s quantization of energy in the Planck radiation law, which introduced the concept that energy is emitted or absorbed in discrete packets called quanta.
Thus, the Rayleigh-Jeans assumption in option (A) directly leads to the ultraviolet catastrophe.
At a particular temperature T, Planck's energy density of black body radiation in terms of frequency is \(\rho_T(\nu) = 8 \times 10^{-18} \text{ J/m}^3 \text{ Hz}^{-1}\) at \(\nu = 3 \times 10^{14}\) Hz. Then Planck's energy density \(\rho_T(\lambda)\) at the corresponding wavelength (\(\lambda\)) has the value \rule{1cm}{0.15mm} \(\times 10^2 \text{ J/m}^4\). (in integer)
[Speed of light \(c = 3 \times 10^8\) m/s]
(Note: The unit for \(\rho_T(\nu)\) in the original problem was given as J/m³, which is dimensionally incorrect for a spectral density. The correct unit J/(m³·Hz) or J·s/m³ is used here for the solution.)