Question:
The transition metal (M) complex that can have all isomers (geometric, linkage, and ionization) is
The transition metal (M) complex that can have all isomers (geometric, linkage, and ionization) is
Updated On: Dec 29, 2024
- [M(NH3)4Br2]SCN
- [M(NH3)4Cl2]Br
- [M(NH3)4(H2O)2]Cl3
- [M(NH3)4 (H2O)2](SCN)3
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The Correct Option is A
Solution and Explanation
The correct option is (A): [M(NH3)4Br2]SCN
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