The given expression is \( (x + y)^{100} + (x - y)^{100} \). To find the total number of terms in the expansion of this expression, we will first analyze the individual expansions of \( (x + y)^{100} \) and \( (x - y)^{100} \), and then combine them.
The binomial expansion of \( (x + y)^{100} \) is given by:
\[ (x + y)^{100} = \sum_{k=0}^{100} \binom{100}{k} x^{100-k} y^k \]
This expansion has \( 101 \) terms because the index \( k \) ranges from 0 to 100, inclusive. So, the expansion of \( (x + y)^{100} \) contains 101 terms.
The binomial expansion of \( (x - y)^{100} \) is given by:
\[ (x - y)^{100} = \sum_{k=0}^{100} \binom{100}{k} x^{100-k} (-y)^k = \sum_{k=0}^{100} \binom{100}{k} (-1)^k x^{100-k} y^k \]
Like the first expansion, this also has \( 101 \) terms. However, the signs of the terms alternate depending on whether \( k \) is even or odd due to the factor \( (-1)^k \). So, the expansion of \( (x - y)^{100} \) also contains 101 terms.
Now, consider the sum of the two expansions:
\[ (x + y)^{100} + (x - y)^{100} \] When we add these two expansions, terms where the powers of \( y \) are odd will cancel each other out, because \( (-y)^k \) will have the opposite sign of \( y^k \) when \( k \) is odd. On the other hand, terms where \( k \) is even will add up, because both expansions will have the same sign for those terms.
Thus, only the terms where \( k \) is even will remain after addition. The even values of \( k \) range from 0 to 100, inclusive. These values are \( k = 0, 2, 4, \dots, 100 \), which gives a total of 51 even values.
The total number of terms in the expansion of \( (x + y)^{100} + (x - y)^{100} \) is 51, because only the terms with even values of \( k \) survive after adding the two expansions
The term independent of $ x $ in the expansion of $$ \left( \frac{x + 1}{x^{3/2} + 1 - \sqrt{x}} \cdot \frac{x + 1}{x - \sqrt{x}} \right)^{10} $$ for $ x>1 $ is:
Let $ (1 + x + x^2)^{10} = a_0 + a_1 x + a_2 x^2 + ... + a_{20} x^{20} $. If $ (a_1 + a_3 + a_5 + ... + a_{19}) - 11a_2 = 121k $, then k is equal to _______
In the expansion of \[ \left( \sqrt[3]{2} + \frac{1}{\sqrt[3]{3}} \right)^n , \, n \in \mathbb{N}, \] if the ratio of the 15th term from the beginning to the 15th term from the end is \[ \frac{1}{6}, \] then the value of \[ {}^nC_3 \] is:
A solid cylinder of mass 2 kg and radius 0.2 m is rotating about its own axis without friction with angular velocity 5 rad/s. A particle of mass 1 kg moving with a velocity of 5 m/s strikes the cylinder and sticks to it as shown in figure. 
The angular velocity of the system after the particle sticks to it will be: