The given curve is:
\[
y = x^3 + 3x^2 + 5.
\]
Step 1: Find the slope of the tangent.
The derivative of \( y \) with respect to \( x \) is:
\[
\frac{dy}{dx} = 3x^2 + 6x.
\]
Step 2: Equation of the tangent.
The equation of the tangent line at the point \( (x_1, y_1) \) is:
\[
y - y_1 = (3x_1^2 + 6x_1)(x - x_1).
\]
Step 3: Condition for the tangent to pass through the origin.
Substitute the coordinates \( (0, 0) \) into the tangent equation:
\[
0 - y_1 = (3x_1^2 + 6x_1)(0 - x_1).
\]
Simplify the equation:
\[
y_1 = x_1(3x_1 + 6) = 3x_1^2 + 6x_1.
\]
Step 4: Check if the curve satisfies the condition.
Substitute \( x_1 \) and \( y_1 \) into the equation \( \frac{x}{3} - y^2 = 2 \).
The equation is not satisfied, thus confirming the incorrect answer.
Therefore, the correct answer is \( \boxed{(4)} \).