Let the two numbers be \( x \) and \( y \). We are given the system of equations:
\[
x + y = 11 \quad \text{and} \quad x \times y = 30
\]
We can solve these equations using the quadratic equation. Substitute \( y = 11 - x \) into the second equation:
\[
x \times (11 - x) = 30
\]
\[
x^2 - 11x + 30 = 0
\]
Factoring the quadratic equation:
\[
(x - 6)(x - 5) = 0
\]
Thus, \( x = 6 \) and \( y = 5 \) (or vice versa). Therefore, the correct answer is \( 6, 5 \).