In the compound \( Na_2O_2 \) (sodium peroxide), the oxidation number of oxygen is -1 in the peroxide ion (\( O_2^{2-} \)). However, in compounds like \( F_2O \), oxygen has an oxidation state of +2 (since fluorine is more electronegative). \( O_3 \) (ozone) has an oxidation state of 0 for oxygen. Thus, the correct compound where the oxidation number of oxygen is +2 is \( Na_2O_2 \).
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