Question

The sum of three binary numbers, 10110.10, 11010.01, and 10101.11, in decimal system is:

• A. 70.75
• B. 70.25
• C. 70.50
• D. 69.50

Answer 1

The Correct Option is C

Step 1: Convert Binary Numbers to Decimal

1. \( 10110.10_2 \): Convert to decimal: \[ 10110_2 = 22, \quad 0.10_2 = 0.5 \] \[ 10110.10_2 = 22.5_{10} \]
2. \( 11010.01_2 \): Convert to decimal: \[ 11010_2 = 26, \quad 0.01_2 = 0.25 \] \[ 11010.01_2 = 26.25_{10} \]
3. \( 10101.11_2 \): Convert to decimal: \[ 10101_2 = 21, \quad 0.11_2 = 0.75 \] \[ 10101.11_2 = 21.75_{10} \]

Step 2: Add the Decimal Numbers

Now, add the converted decimal numbers:

\[ 22.5 + 26.25 + 21.75 = 70.50 \]

Conclusion:

Therefore, the sum of the binary numbers in the decimal system is:

\[ \boxed{70.50} \]