Question

The sum of the zeroes of the quadratic polynomial \( 4x^2 - 4x + 1 \) will be:

• A. 1
• B. 4
• C. -4
• D. $\dfrac{1}{4}$

Hint:

For any quadratic equation \( ax^2 + bx + c \), the sum of roots \( = -\frac{b}{a} \) and the product \( = \frac{c}{a} \).

Answer 1

The Correct Option is A

Step 1: Recall the formula for the sum of zeroes.
For a quadratic polynomial \( ax^2 + bx + c \), the sum of its zeroes is given by \[ \alpha + \beta = -\frac{b}{a} \]
Step 2: Identify coefficients.
In \( 4x^2 - 4x + 1 \), we have: \[ a = 4, \quad b = -4, \quad c = 1 \]
Step 3: Apply the formula.
\[ \alpha + \beta = -\frac{-4}{4} = \frac{4}{4} = 1 \]
Step 4: Conclusion.
Hence, the sum of the zeroes of the given quadratic polynomial is \( 1 \).