The sum of the magnitudes of two vectors $\vec{A$ and $\vec{B}$ is $8$ and magnitude of the resultant is $4$. If the resultant vector is perpendicular to any one vector, then the magnitudes of the two vectors $\vec{A}$ and $\vec{B}$ are}
Show Hint
Use Pythagoras theorem when the vectors are perpendicular and their sum is given.
Step 1: Vector addition.
Let magnitudes of vectors $\vec{A}$ and $\vec{B}$ be $a$ and $b$ respectively.
From the given information:
\[
a + b = 8
\]
Resultant magnitude of perpendicular vectors:
\[
R = \sqrt{a^2 + b^2} = 4
\]
\[
a^2 + b^2 = 16
\]
Step 2: Solving the system of equations.
We now solve the system:
\[
a + b = 8
\]
\[
a^2 + b^2 = 16
\]
By solving, we get $a = 3$ and $b = 5$.
Step 3: Conclusion.
The magnitudes of the two vectors are $3$ and $5$.