(I) At pH = 2
(highly acidic), the structure of the peptide will be as shown below.
Net charge +2
|Z1| = 2 at pH = 2
(ii) At pH = 6 (neutral solution)
In neutral medium, the given tripeptide exists as Zwitter ion.
net charge = 0
|Z2| = 0 at pH = 6
(iii)At pH = 11 (basic medium)
In basic medium the given tripeptide exists in anionic form.
Net charge = β3
So, |Z3| = |-3|
|Z1| + |Z2| + |Z3| = 2 + 0 + 3 = 5
Write the reaction of D-Glucose with the following:
$\text{HCN}$
$\text{Br}_2 \text{water} $
$\text{(CH}_3\text{COO)}_2 \text{O}$
Figure 1 shows the configuration of main scale and Vernier scale before measurement. Fig. 2 shows the configuration corresponding to the measurement of diameter $ D $ of a tube. The measured value of $ D $ is: