Question:

The structure of a peptide is given below:

If the absolute values of the net charge of the peptide at $pH =2, pH =6$, and $pH =11$ are $\left| z _{1}\right|,\left| z _{2}\right|$, and $\left| z _{3}\right|$, respectively, then what is $\left|z_{1}\right|+\left|z_{2}\right|+\left|z_{3}\right|$ ?

JEE Advanced - 2020
JEE Advanced

Updated On: May 21, 2024

Hide Solution

Verified By Collegedunia

Correct Answer: 5

Solution and Explanation

(I) At pH = 2
(highly acidic), the structure of the peptide will be as shown below.

Net charge +2

|Z₁| = 2 at pH = 2

(ii) At pH = 6 (neutral solution)

In neutral medium, the given tripeptide exists as Zwitter ion.

net charge = 0

|Z₂| = 0 at pH = 6

(iii)At pH = 11 (basic medium)

In basic medium the given tripeptide exists in anionic form.

Net charge = –3
So, |Z3| = |-3|

|Z₁| + |Z₂| + |Z₃| = 2 + 0 + 3 = 5

Was this answer helpful?

Questions Asked in JEE Advanced exam

Consider the ellipse $\frac{x^2}{9}+\frac{y^2}{4}=1$. Let S (p, q) be a point in the first quadrant such that $\frac{p^2}{9}+\frac{q^2}{4}>1$. Two tangents are drawn from S to the ellipse, of which one meets the ellipse at one end point of the minor axis and the other meets the ellipse at a point T in the fourth quadrant. Let R be the vertex of the ellipse with positive x-coordinate and Obe the center of the ellipse. If the area of the triangle △ORT is $\frac{3}{2}$ , then which of the following options is correct ?
- JEE Advanced - 2024
- Conic sections
View Solution
Among V(CO)₆, Cr(CO)₅, Cu(CO)₃, Mn(CO)₅, Fe(CO)₅, [Co(CO)₃]^3-, [Cr(CO)₄]^4-, and Ir(CO)₃, the total number of species isoelectronic with Ni(CO)₄ is _________.
[Given, atomic number: V = 23, Cr=24, Mn 25, Fe 26, Co 27, Ni 28, Cu = 29, Ir = 77]
- JEE Advanced - 2024
- Isomerism in Coordination Compounds
View Solution
Let $\overrightarrow{OP}=\frac{\alpha-1}{\alpha}\hat{i}+\hat{j}+\hat{k},\overrightarrow{OQ}=\hat{i}+\frac{\beta-1}{\beta}\hat{j}+\hat{k}$ and $\overrightarrow{OR}=\hat{i}+\hat{j}+\frac{1}{2}\hat{k}$ be three vector where α, β ∈ R - {0} and 0 denotes the origin. If $(\overrightarrow{OP}\times\overrightarrow{OQ}).\overrightarrow{OR}=0$ and the point (α, β, 2) lies on the plane 3x + 3y - z + l = 0, then the value of l is _______.
- JEE Advanced - 2024
- Vector Algebra
View Solution
A closed vessel contains 10 g of an ideal gas X at 300 K, which exerts 2 atm pressure. At the same temperature, 80 g of another ideal gas Y is added to it and the pressure becomes 6 atm. The ratio of root mean square velocities of X and Y at 300 K is
- JEE Advanced - 2024
- States of matter
View Solution
Let the function $f:[1,\infin)→\R$ be defined by
$f(t) = \begin{cases} (-1)^{n+1}2, & \text{if } t=2n-1,n\in\N, \\ \frac{(2n+1-t)}{2}f(2n-1)+\frac{(t-(2n-1))}{2}f(2n+1) & \text{if } 2n-1<t<2n+1,n\in\N. \end{cases}$
Define $g(x)=\int\limits_{1}^{x}f(t)dt,x\in(1,\infin).$ Let α denote the number of solutions of the equation g(x) = 0 in the interval (1, 8] and $β=\lim\limits_{x→1+}\frac{g(x)}{x-1}$. Then the value of α + β is equal to _____.
- JEE Advanced - 2024
- Integral Calculus
View Solution

View More Questions

The structure of a peptide is given below: If the absolute values of the net charge of the peptide at $pH =2, pH =6$, and $pH =11$ are $\left| z _{1}\right|,\left| z _{2}\right|$, and $\left| z _{3}\right|$, respectively, then what is $\left|z_{1}\right|+\left|z_{2}\right|+\left|z_{3}\right|$ ?

Correct Answer: 5

Solution and Explanation

Top Questions on Biomolecules

Questions Asked in JEE Advanced exam

The structure of a peptide is given below:

If the absolute values of the net charge of the peptide at $pH =2, pH =6$, and $pH =11$ are $\left| z _{1}\right|,\left| z _{2}\right|$, and $\left| z _{3}\right|$, respectively, then what is $\left|z_{1}\right|+\left|z_{2}\right|+\left|z_{3}\right|$ ?