Question:
The strength of $11.2$ volume solution of $H_2O_2$ is : [Given that molar mass of $H = 1\, g$ $mol^{-1}$ and $O = 16\, g\, mol^{-1}]$
The strength of $11.2$ volume solution of $H_2O_2$ is : [Given that molar mass of $H = 1\, g$ $mol^{-1}$ and $O = 16\, g\, mol^{-1}]$
Updated On: Sep 14, 2024
- $13.6\%$
- $3.4\%$
- $34\%$
- $1.7\%$
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The Correct Option is B
Solution and Explanation
$\underset{\text{68 g/L}}{ {2H2O2}} $$ {->2H2O \,+}$ $\underset{\text{22.4of $O_2$ (STP)}}{ {O2 ?}}$
11.2 L of O is given by 34 g of HO present in 1 L of HO solution.
So % strength of HO $=\frac{34}{1000}\times100=3.4g/100mL=3.4\%$
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Concepts Used:
Solutions
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
Types of Solutions:
The solutions can be classified into three types:
- Solid Solutions - In these solutions, the solvent is in a Solid-state.
- Liquid Solutions- In these solutions, the solvent is in a Liquid state.
- Gaseous Solutions - In these solutions, the solvent is in a Gaseous state.
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types:
- Unsaturated Solution- A solution in which more solute can be dissolved without raising the temperature of the solution is known as an unsaturated solution.
- Saturated Solution- A solution in which no solute can be dissolved after reaching a certain amount of temperature is known as an unsaturated saturated solution.
- Supersaturated Solution- A solution that contains more solute than the maximum amount at a certain temperature is known as a supersaturated solution.