Direction vector of line = \( \vec{d} = \langle 2, 1, -1 \rangle \)
Normal vector of plane = \( \vec{n} = \langle 2, 1, -1 \rangle \)
If dot product = 0 → perpendicular.
\[
\vec{d} \cdot \vec{n} = 2 \cdot 2 + 1 \cdot 1 + (-1)\cdot(-1) = 4 + 1 + 1 = 6 \neq 0
\]
Wait! But direction vector of line is same as normal to plane ⇒ they are perpendicular.