We verify the equivalence of \( B \Rightarrow ((\sim A) \lor B) \) by using truth tables.
Step 1: Analyze the given expression The statement is \( B \Rightarrow ((\sim A) \lor B) \). By the definition of implication: \[ P \Rightarrow Q \equiv (\sim P) \lor Q, \] the statement can be rewritten as: \[ (\sim B) \lor ((\sim A) \lor B). \]
Step 2: Construct the truth table for \( B \Rightarrow ((\sim A) \lor B) \)

Step 3: Verify equivalence with the options
(A) Option (1): \( B \Rightarrow (A \Rightarrow B) \) Simplify \( A \Rightarrow B \equiv (\sim A) \lor B \). Thus: \[ B \Rightarrow ((\sim A) \lor B). \] The truth table matches exactly with \( B \Rightarrow ((\sim A) \lor B) \).
(B)Option (3): \( A \Rightarrow ((\sim A) \Rightarrow B) \) Simplify \( (\sim A) \Rightarrow B \equiv A \lor B \). Thus: \[ A \Rightarrow ((\sim A) \lor B) \equiv (\sim A) \lor ((\sim A) \lor B), \] which matches the truth table of \( B \Rightarrow ((\sim A) \lor B) \).
(C)Option (4): \( B \Rightarrow ((\sim A) \Rightarrow B) \) Simplify \( (\sim A) \Rightarrow B \equiv A \lor B \). Thus: \[ B \Rightarrow (A \lor B), \] which also matches the truth table of \( B \Rightarrow ((\sim A) \lor B) \).
Two circular discs of radius \(10\) cm each are joined at their centres by a rod, as shown in the figure. The length of the rod is \(30\) cm and its mass is \(600\) g. The mass of each disc is also \(600\) g. If the applied torque between the two discs is \(43\times10^{-7}\) dyne·cm, then the angular acceleration of the system about the given axis \(AB\) is ________ rad s\(^{-2}\).

Method used for separation of mixture of products (B and C) obtained in the following reaction is: 
Mathematical reasoning or the principle of mathematical reasoning is a part of mathematics where we decide the truth values of the given statements. These reasoning statements are common in most competitive exams like JEE and the questions are extremely easy and fun to solve.
Mathematically, reasoning can be of two major types such as: