Question:

The standing wave ratio of an open wire transmission line having a characteristic impedance of 600\(\Omega\) and terminated by resistive load of 900\(\Omega\) will be ________.

Show Hint

If the load and characteristic impedance match, SWR = 1. A mismatch results in \(SWR>1\). Use the ratio \(Z_L/Z_0\) or \(Z_0/Z_L\) depending on which is larger.
Updated On: July 22, 2025
  • 1
  • 2
  • 1.5
  • 4
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is C

Solution and Explanation

The formula for standing wave ratio (SWR) is: \[ SWR = \frac{Z_L}{Z_0} \text{if } Z_L>Z_0 \] Here, \[ Z_0 = 600~\Omega, Z_L = 900~\Omega \Rightarrow SWR = \frac{900}{600} = 1.5 \] Final Answer: (3) 1.5
Was this answer helpful?
0
0

AP PGECET Notification