Step 1: Determine the value of X (the spot speed of the fourth vehicle)
The Time Mean Speed (TMS) is given by the formula: \[ TMS = \frac{V_1 + V_2 + V_3 + \cdots + V_n}{n} \] where:
\( V_1, V_2, \dots, V_n \) are the spot speeds of the vehicles,
\( n \) is the number of vehicles.
Given that:
The Time Mean Speed (TMS) is 56.25 km/h,
The spot speeds are 42, 52, 56, \( X \), 53, 62, 65, 48.
We can use the formula for Time Mean Speed: \[ 56.25 = \frac{42 + 52 + 56 + X + 53 + 62 + 65 + 48}{8} \] Simplifying the equation: \[ 56.25 = \frac{378 + X}{8} \] Multiplying both sides by 8: \[ 450 = 378 + X \] Solving for \( X \): \[ X = 450 - 378 = 72 \] So, the spot speed of the fourth vehicle, \( X \), is 72 km/h.
Step 2: Calculate the Space Mean Speed (SMS)
The Space Mean Speed (SMS) is given by the formula: \[ SMS = \frac{n}{\frac{1}{V_1} + \frac{1}{V_2} + \cdots + \frac{1}{V_n}} \] Substituting the values for the spot speeds (42, 52, 56, 72, 53, 62, 65, 48) into the formula: \[ SMS = \frac{8}{\frac{1}{42} + \frac{1}{52} + \frac{1}{56} + \frac{1}{72} + \frac{1}{53} + \frac{1}{62} + \frac{1}{65} + \frac{1}{48}} \] Calculating the reciprocals: \[ \frac{1}{42} = 0.02381, \quad \frac{1}{52} = 0.01923, \quad \frac{1}{56} = 0.01786 \] \[ \frac{1}{72} = 0.01389, \quad \frac{1}{53} = 0.01887, \quad \frac{1}{62} = 0.01613 \] \[ \frac{1}{65} = 0.01538, \quad \frac{1}{48} = 0.02083 \] Summing these reciprocals: \[ 0.02381 + 0.01923 + 0.01786 + 0.01389 + 0.01887 + 0.01613 + 0.01538 + 0.02083 = 0.13501 \] Now, calculating the Space Mean Speed: \[ SMS = \frac{8}{0.13501} \approx 59.26 \, {km/h} \]
Conclusion: The Space Mean Speed (SMS) of the traffic stream is 59.26 km/h (rounded to two decimal places).
A four-arm uncontrolled un-signaled urban intersection of both-way traffic is illustrated in the figure. Vehicles approaching the intersection from the directions A, B, C, and D can move to either left, right, or continue in straight direction. No U-turn is allowed. In the given situation, the maximum number of vehicular crossing conflict points for this intersection is _________ (answer in integer)
Group I | Group II |
(P) Floating floor | (1) Overflow control |
(Q) Float valve | (2) Delay not affecting a project |
(R) Metal float | (3) Acoustical buffer |
(S) Free float | (4) Plastering equipment |
(5) Traffic flow control |
Fish : Shoal :: Lion : _________
Select the correct option to complete the analogy.
P and Q play chess frequently against each other. Of these matches, P has won 80% of the matches, drawn 15% of the matches, and lost 5% of the matches.
If they play 3 more matches, what is the probability of P winning exactly 2 of these 3 matches?
The given figure is reflected about the horizontal dashed line and then rotated clockwise by 90° about an axis perpendicular to the plane of the figure.
Which one of the following options correctly shows the resultant figure?
Note: The figures shown are representative