The first law of thermodynamics gives: \[ dQ = du + dW \]
At constant pressure, this becomes: \[ C dT = C_v dT + P dV \tag{1} \]
Given \( PV^2 = RT \), differentiating both sides with respect to \( T \) at constant \( P \): \[ P(2V dV) = R dT \] \[ P dV = \frac{R}{2V} dT \]
Substitute \( P dV \) into equation (1): \[ C dT = C_v dT + \frac{R}{2V} dT \] \[ C = C_v + \frac{R}{2V} \]
Thus, the specific heat at constant pressure is: \[ C = C_v + \frac{R}{2V}. \]
Choose the correct set of reagents for the following conversion:
A bead of mass \( m \) slides without friction on the wall of a vertical circular hoop of radius \( R \) as shown in figure. The bead moves under the combined action of gravity and a massless spring \( k \) attached to the bottom of the hoop. The equilibrium length of the spring is \( R \). If the bead is released from the top of the hoop with (negligible) zero initial speed, the velocity of the bead, when the length of spring becomes \( R \), would be (spring constant is \( k \), \( g \) is acceleration due to gravity):