The freezing point depression is directly related to the number of particles in solution, as per the formula:
\[
\Delta T_f = i \cdot K_f \cdot m
\]
Where:
- \( \Delta T_f \) is the freezing point depression
- \( i \) is the van 't Hoff factor (number of particles produced in solution)
- \( K_f \) is the cryoscopic constant (depends on the solvent)
- \( m \) is the molality of the solution
The van 't Hoff factor \( i \) is highest for salts that dissociate into more ions.
- K\(_2\)SO\(_4\) dissociates into 3 ions (K\(^+\), K\(^+\), SO\(_4^{2-}\))
- KCl dissociates into 2 ions (K\(^+\), Cl\(^-\))
- NaNO\(_3\) dissociates into 2 ions (Na\(^+\), NO\(_3^-\))
- MgSO\(_4\) dissociates into 2 ions (Mg\(^{2+}\), SO\(_4^{2-}\))
Thus, the solution with the lowest freezing point depression is the one with the highest number of ions, which is 0.2M K\(_2\)SO\(_4\).