Step 1: Identify coefficients.
For the equations:
1) $x + 2y + 5 = 0$, coefficients are $a_1 = 1$, $b_1 = 2$, $c_1 = 5$.
2) $-3x - 6y + 1 = 0$, coefficients are $a_2 = -3$, $b_2 = -6$, $c_2 = 1$.
Step 2: Check the ratios.
\[
\frac{a_1}{a_2} = \frac{1}{-3}, \quad \frac{b_1}{b_2} = \frac{2}{-6} = \frac{1}{-3}, \quad \frac{c_1}{c_2} = \frac{5}{1} = 5
\]
Since $\frac{a_1}{a_2} = \frac{b_1}{b_2} \neq \frac{c_1}{c_2}$, the lines are parallel and have no solution.
Step 3: Conclusion.
Therefore, the pair of linear equations has no solution.