Question

The solidification of a cubical casting of side 100 mm takes place with volumetric solidification shrinkage and solid contraction of 10% each. The shape of the casting is retained on cooling to room temperature. The side of the cubical cast, in mm, at room temperature is ................. (round off to 2 decimal places).

Hint:

When calculating dimensional changes due to shrinkage in casting, always consider the combined effect of solidification shrinkage and solid contraction.

Answer 1

- The total shrinkage is the sum of volumetric shrinkage and solid contraction. Each is 10% shrinkage. Therefore, the total shrinkage is: \[ \text{Total Shrinkage} = 1 - (1 - 0.1)(1 - 0.1) = 1 - 0.9 \times 0.9 = 0.19 \] - The side of the casting at room temperature will be the initial side minus 19% shrinkage: \[ \text{Side at room temperature} = 100 \times (1 - 0.19) = 100 \times 0.81 = 81.00 \text{ mm}. \]