The signal-to-noise ratio (SNR) of an ADC with a full-scale sinusoidal input is given to be 61.96 dB. The resolution of the ADC is ___________ bits (rounded off to the nearest integer).
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Correct Answer: 10
Solution and Explanation
SNR (dB) = $6.02n + 1.76$ dB
Where 'n' is the number of bits (resolution) of the ADC.
We are given that SNR = 61.96 dB. We can substitute this value into the formula and solve for n.
$61.96 = 6.02n + 1.76$
Subtract 1.76 from both sides:
$61.96 - 1.76 = 6.02n$
$60.2 = 6.02n$
Now, divide by 6.02 to find n:
$n = \frac{60.2}{6.02} = 10$
The resolution of the ADC is 10 bits. The result is an integer, so no rounding is needed.
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