Question:

The sides of a rectangle are given by $x = \pm \, a$ and $y = \pm \, b$. The equation of the circle passing through the vertices of the rectangle is

Updated On: May 7, 2024
  • $x^2 + y^2 = a^2$
  • $x^2 + y^2 = a^2 + b^2 $
  • $x^2 + y^2 = a^2 - b^2 $
  • $\left(x -a\right)^{2}+ \left(y-b\right)^{2} = a^{2} + b^{2} $
Hide Solution
collegedunia
Verified By Collegedunia

The Correct Option is B

Solution and Explanation

Given sides of rectangle are $x=\pm a$ and $ y=\pm b $ $\therefore$ Centre of circle $=(0,0)$ and radius of circle $=\sqrt{a^{2}+b^{2}}$
$\therefore$ Equation of circle $x^2 + y^2 = (a^2 + b^2)$
Was this answer helpful?
22
2

Top Questions on Conic sections

View More Questions