Step 1: Compute the first derivative
For \( f(x) \) to be strictly increasing, its first derivative must be positive for all \( x \):
\[
f'(x) = 3x^2 + 4ax + 3(a+1).
\]
Step 2: Ensure positivity of \( f'(x) \)
The quadratic expression \( 3x^2 + 4ax + 3(a+1)0 \) must be always positive, meaning its discriminant must be negative:
\[
\Delta = (4a)^2 - 4(3)(3a+3)0.
\]
Solving for \( a \):
\[
16a^2 - 36a - 360.
\]
Factoring and solving the inequality, we find the valid range:
\[
\left( -\frac{3}{4}, 3 \right).
\]