Question:
The relationship between solubility of a gas in a liquid at constant temperature and external pressure is:
The relationship between solubility of a gas in a liquid at constant temperature and external pressure is:
Show Hint
Henry’s law states that the higher the pressure of a gas, the greater its solubility in a liquid at constant temperature.
Updated On: Jan 16, 2025
- \( S \propto \frac{1}{P} \)
- \( S \propto P \)
- \( S \propto P^2 \)
- None of the above
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
According to Henry’s law, the solubility of a gas (\( S \)) in a liquid is directly proportional to the external pressure (\( P \)) at a constant temperature.
Conclusion: The relationship is \( S \propto P \).
Conclusion: The relationship is \( S \propto P \).
Was this answer helpful?
0
0
Top Questions on Gas laws
- What is the rate law if the rate is directly proportional to \([B]^2\) and independent of \([A]\)?
- The compressibility factor for a van der Waals gas at high pressure is
- The work done during reversible isothermal expansion of one mole of hydrogen gas at 25oC from a pressure of 20 atm to 10 atm is:
(Given R = 2.0 cal K-1 mol-1) - The Henry’s law constant (KH) values of three gases (A, B, C) in water are 145, 2 × 10–5 and 35 kbar, respectively. The solubility of these gases in water follow the order :
- Which plot of ln k vs \(\frac{1}{T}\) is consistent with Arrhenius equation?
View More Questions
Questions Asked in MHT CET exam
- In 2-chloro-3,4-dimethylhexane, how many chiral carbon atoms are present?
- MHT CET - 2024
- Chemical Kinetics
- The number of ways of distributing \( 500 \) dissimilar boxes equally among \( 50 \) persons is
- MHT CET - 2024
- Permutations
- Which of the following alkanes is tertiary?
- MHT CET - 2024
- Organic Chemistry- Some Basic Principles and Techniques
- The statement \( (p \wedge (\sim q)) \vee ((\sim p) \wedge q) \vee ((\sim p) \wedge (\sim q)) \) is equivalent to:
- MHT CET - 2024
- Algebra of Complex Numbers
- If the lines \( \frac{x-k}{2} = \frac{y+1}{3} = \frac{z-1}{4} \) and \( \frac{x-3}{1} = \frac{y - 9/2}{2} = z/1 \) intersect, then the value of \( k \) is:
- MHT CET - 2024
- Derivatives of Functions in Parametric Forms
View More Questions