Question

The refracting angle of a prism of refractive index \( \sqrt{3} \) is equal to its angle of minimum deviation. The value of angle of minimum deviation is:

• A. \( 30^\circ \)
• B. \( 45^\circ \)
• C. \( 60^\circ \)
• D. \( 120^\circ \)

Hint:

In an equilateral prism with refractive index \( \sqrt{3} \), the minimum deviation angle equals the prism angle.

Answer 1

The Correct Option is C

Step 1: The formula for minimum deviation is: \[ \delta_{\min} = 2 \theta - A \] Step 2: Given \( A = 60^\circ \) and \( \mu = \sqrt{3} \), we solve for \( \delta_{\min} \). \[ \boxed{\delta_{\min} = 60^\circ} \]