Ozonolysis of but-2-ene in the presence of water and zinc dust breaks the double bond, forming two carbonyl compounds. The further reduction of ozonolysis products gives ethanol.
- Step 1: Ozone cleaves the double bond, forming two aldehydes or ketones.
- Step 2: Reduction with Zn/H\(_2\)O converts one of the fragments into ethanol.
Thus, the correct reagent for this conversion is O\(_3\)/H\(_2\)O-Zn dust.
For the reaction:
\[ 2A + B \rightarrow 2C + D \]
The following kinetic data were obtained for three different experiments performed at the same temperature:
\[ \begin{array}{|c|c|c|c|} \hline \text{Experiment} & [A]_0 \, (\text{M}) & [B]_0 \, (\text{M}) & \text{Initial rate} \, (\text{M/s}) \\ \hline I & 0.10 & 0.10 & 0.10 \\ II & 0.20 & 0.10 & 0.40 \\ III & 0.20 & 0.20 & 0.40 \\ \hline \end{array} \]
The total order and order in [B] for the reaction are respectively: