Step 1: Understand the Hydrolysis Reactions of Xenon Fluorides
When xenon fluorides ($ \text{XeF}_2 $, $ \text{XeF}_4 $, and $ \text{XeF}_6 $) undergo complete hydrolysis, they produce different products depending on their oxidation states and reactivity with water. Let's analyze each case:
Step 2: Analyze Each Reaction
% Option
(I) Complete Hydrolysis of $ \text{XeF}_2 $
$ \text{XeF}_2 $ undergoes hydrolysis to form xenon gas ($ \text{Xe} $) and hydrogen fluoride ($ \text{HF} $):
$$
\text{XeF}_2 + 2\text{H}_2\text{O} \rightarrow \text{Xe} + 4\text{HF}
$$
No $ \text{XeO}_3 $ is formed.
% Option
(II) Complete Hydrolysis of $ \text{XeF}_4 $
$ \text{XeF}_4 $ undergoes hydrolysis to form $ \text{XeO}_3 $, hydrogen fluoride ($ \text{HF} $), and oxygen ($ \text{O}_2 $):
$$
\text{XeF}_4 + 2\text{H}_2\text{O} \rightarrow \text{XeO}_3 + 4\text{HF} + \frac{1}{2}\text{O}_2
$$
$ \text{XeO}_3 $ is formed.
% Option
(III) Complete Hydrolysis of $ \text{XeF}_6 $
$ \text{XeF}_6 $ undergoes hydrolysis to form $ \text{XeO}_3 $, hydrogen fluoride ($ \text{HF} $), and oxygen ($ \text{O}_2 $):
$$
\text{XeF}_6 + 3\text{H}_2\text{O} \rightarrow \text{XeO}_3 + 6\text{HF} + \frac{3}{2}\text{O}_2
$$
$ \text{XeO}_3 $ is formed.
Step 3: Identify the Correct Option
From the analysis:
I) Complete hydrolysis of $ \text{XeF}_2 $ does not produce $ \text{XeO}_3 $.
II) Complete hydrolysis of $ \text{XeF}_4 $ produces $ \text{XeO}_3 $.
III) Complete hydrolysis of $ \text{XeF}_6 $ produces $ \text{XeO}_3 $.
Thus, the correct reactions that give $ \text{XeO}_3 $ as a product are II and III.
Step 4: Match with Options
Option (1): I& II only
Incorrect — $ \text{XeF}_2 $ does not produce $ \text{XeO}_3 $.
Option (2): II& III only
Correct — matches the analysis.
Option (3): I& III only
Incorrect — $ \text{XeF}_2 $ does not produce $ \text{XeO}_3 $.
Option (4): I, II, III
Incorrect — $ \text{XeF}_2 $ does not produce $ \text{XeO}_3 $.