Comprehension
The reaction of x g of Sn with HCl quantitatively produced a salt. The entire amount of the salt reacted with y g of nitrobenzene in the presence of the required amount of HCl to produce 1.29 g of an organic salt (quantitatively).
(Use Molar masses (in g mol–1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively).
(Use Molar masses (in g mol–1) of H, C, N, O, Cl and Sn as 1, 12, 14, 16, 35 and 119, respectively).
Question: 1
The value of x is ________.
The value of x is ________.
Updated On: May 23, 2024
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Correct Answer: 3.57
Solution and Explanation
Sn + HCl → SnCl2
\(⇒\) Moles of ammonium salt =\(\frac{1.29}{129} = 0.01\)
\(⇒\) Moles of nitrobenzene = 0.01
No. of eq. of nitrobenzene = No. of eq. of SnCl2
6 × (0.01) = 2 ×n SnCl2
= 0.03
\(⇒\) nSn = 0.03
wSn = 0.03 × 119
x = 3.57
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Question: 2
The value of y is ________.
The value of y is ________.
Updated On: May 23, 2024
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Correct Answer: 1.23
Solution and Explanation
Sn + HCl → SnCl2
\(⇒\) Moles of ammonium salt = \(\frac{1.29}{129} = 0.01\)
\(⇒\) Moles of nitrobenzene = 0.01
\(⇒\) y = 0.01 × Molar mass of nitrobenzene
= 0.01 × 123
\(= y = 1.23\)
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