Question:
The reaction of propene with $HBr$ in peroxide proceeds through the intermediate
The reaction of propene with $HBr$ in peroxide proceeds through the intermediate
Updated On: June 02, 2025
- $H_3C - \underset{ \bullet} {C} - CH_3 $
- $H_3C - \underset{\bullet}{C} - CH_2 Br $
- $H_3C - \overset{\underset{|}{Br}}{CH} - \overset{\bullet}{C}H_2$
- $ H_3C - CH_2 - \overset{ \bullet}{ C} H_2$
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The Correct Option is B
Solution and Explanation
The intermediate produce in case of addition of $HBr$ occurs according to antimarkonicov's rule. Thus we get
$CH _{3}- \overset{\bullet}{C}H - CH _{2} Br$ as intermidiate.
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KEAM Notification
Concepts Used:
Alkenes
Alkenes
In organic chemistry, an alkene is a hydrocarbon containing a carbon-carbon double bond.[1]
Alkene is often used as synonym of olefin, that is, any hydrocarbon containing one or more double bonds.
Read More: Ozonolysis
IUPAC Nomenclature of Alkenes
- An alkene or cycloalkene is indicated by the suffix (ending) ene.
- For the root name, the longest chain must include both carbon atoms of the double bond.
- The root chain must be numbered beginning at the end closest to a double bond carbon atom. If the double bond is in the chain's centre, the nearest substituent rule is used to determine where the numbering begins.
- If the compound contains more than one double bond, it is named with a diene, triene, or equivalent prefix indicating the number of double bonds, and each double bond is assigned a locator number.
Read More: Unsaturated Hydrocarbon