The problem involves two numbers with a given ratio of 3:4 and their sum is 70. To find the larger number, follow these steps:
Let the two numbers be \(3x\) and \(4x\), reflecting the ratio of 3:4. Their sum is given as:
\[3x + 4x = 70\]
Simplify the equation:
\[7x = 70\]
To find \(x\), divide both sides by 7:
\[x = \frac{70}{7} = 10\]
Now substitute \(x\) back to find the values of the numbers:
The first number is:
\[3x = 3 \times 10 = 30\]
The second number, which is also the larger number, is:
\[4x = 4 \times 10 = 40\]
Therefore, the larger number is 40.