Question:

The ratio of the time periods of the revolution of the electrons in the second and third excited states of hydrogen atom is

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For the time period of electron revolution, remember the relationship with the cube of the principal quantum number.
Updated On: Jun 6, 2025
  • 9 : 16
  • 27 : 64
  • 4 : 9
  • 8 : 27
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The Correct Option is B

Solution and Explanation

The time period of the revolution of an electron in an orbit is proportional to the cube of the principal quantum number, $n^3$. Therefore, the ratio of time periods for the second and third excited states is: $$ \frac{T_2}{T_3} = \left(\frac{n_2}{n_3}\right)^3 = \left(\frac{3}{4}\right)^3 = 27 : 64 $$
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