Step 1: In non-cyclic photophosphorylation, electrons are excited in PS II (Photosystem II), where water molecules are split, releasing oxygen and electrons. These excited electrons are passed along the electron transport chain and used to generate ATPs through chemiosmosis. For every two electrons excited from PS II, 3 ATP molecules are produced in the process.
Step 2: In cyclic phosphorylation, electrons are excited in PS I (Photosystem I), but instead of being passed to NADP+ to form NADPH, they are returned to the electron transport chain. This cycle generates additional ATPs but does not contribute to the production of NADPH. For every two electrons excited from PS I during cyclic phosphorylation, 2 ATP molecules are produced.
Step 3: To form 120 ATPs, the ratio of electrons excited from PS II during non-cyclic phosphorylation to those excited from PS I during cyclic phosphorylation is 2:3. This ratio is essential for maintaining the balance between ATP and NADPH production during the light reactions of photosynthesis.
Conclusion: The correct ratio of electrons excited from PS II (non-cyclic) to PS I (cyclic) to form 120 ATPs is 2:3.
The percentage error in the measurement of mass and velocity are 3% and 4% respectively. The percentage error in the measurement of kinetic energy is:
If \( L, M, N \) are the midpoints of the sides PQ, QR, and RP of triangle \( \Delta PQR \), then \( \overline{QM} + \overline{LN} + \overline{ML} + \overline{RN} - \overline{MN} - \overline{QL} = \):