Let the initial number of coins in box A be 17x and in box B be 7x. When 108 coins are shifted from A to B, the new ratio becomes 37:20. The equation is:
\((17x-108)/(7x+108)=37/20\)
Cross-multiplying gives:
\(20(17x-108)=37(7x+108)\)
Expanding both sides:
\(340x-2160=259x+3996\)
Solving for x, we get:
\(81x=6156\)
\(x=76\)
Initial coins in box A = 17x = 1292; in box B = 7x = 532.
After shifting 108 coins, box A has 1292-108=1184 coins; box B has 532+108=640 coins.
To find further coins to shift for a 1:1 ratio:
Let z be the coins to shift further. Then:
\((1184-z)=(640+z)\)
Solving for z:
\(1184-z=640+z\)
\(1184-640=2z\)
\(544=2z\)
\(z=272\)
Therefore, 272 more coins need to be shifted from A to B to make the ratio 1:1.
The solution value 272 is within the given range [272, 272].
Step 1: Define the initial quantities.
Let the number of coins in box A and box B be 17x and 7x respectively.
Initial coins in A = 17x,
Initial coins in B = 7x.
Step 2: After shifting 108 coins from A to B.
New number of coins:
A: 17x - 108,
B: 7x + 108.
Given that the new ratio is 37 : 20:
(17x - 108) / (7x + 108) = 37 / 20.
Step 3: Solve for x.
Cross-multiply:
20(17x - 108) = 37(7x + 108)
340x - 2160 = 259x + 3996
340x - 259x = 3996 + 2160
81x = 6156
x = 6156 / 81 = 76.
Step 4: Find the current number of coins in each box.
After the first shift:
Coins in A = 17 * 76 - 108 = 1292 - 108 = 1184,
Coins in B = 7 * 76 + 108 = 532 + 108 = 640.
Total coins:
1184 + 640 = 1824.
Step 5: Make the ratio 1:1.
For a 1:1 ratio, both boxes must have:
Target in each box = 1824 / 2 = 912.
Currently, box A has 1184 coins, so coins to be shifted from A to B:
Shift needed = 1184 - 912 = 272.
(Alternatively, let the further shift be y, then:
(1184 - y) / (640 + y) = 1
1184 - y = 640 + y
2y = 544
y = 272.
Thus, the number of coins that must be shifted further from A to B is 272.
A shopkeeper marks his goods 40% above cost price and offers a discount of 20%. What is his overall profit percentage?
Health insurance plays a vital role in ensuring financial protection and access to quality healthcare. In India, however, the extent and nature of health insurance coverage vary significantly between urban and rural areas. While urban populations often have better access to organized insurance schemes, employer-provided coverage, and awareness about health policies, rural populations face challenges such as limited outreach of insurance schemes, inadequate infrastructure, and lower awareness levels. This urban-rural divide in health insurance coverage highlights the broader issue of healthcare inequality, making it essential to analyze the factors contributing to this gap and explore strategies for more inclusive health protection. A state-level health survey was conducted.
The survey covered 1,80,000 adults across urban and rural areas. Urban residents formed 55% of the sample (that is, 99,000 people) while rural residents made up 45% (that is, 81,000 people). In each area, coverage was classified under four heads – Public schemes, Private insurance, Employer-provided coverage, and Uninsured. In urban areas, Public coverage accounted for 28% of the urban population, Private for 22%, Employer for 18%, and the remaining 32% were Uninsured. In rural areas, where formal coverage is generally lower, Public coverage stood at 35%, Private at 10%, Employer at 8%, while 47% were Uninsured.
For this survey, “Insured” includes everyone covered by Public + Private + Employer schemes, and “Uninsured” indicates those with no coverage at all. Officials noted that public schemes remain the backbone of rural coverage, while employer and private plans are relatively more prevalent in urban centres. (250 words)
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: