Question:

The ratio of the magnitudes of electric field to the magnetic field of an electromagnetic wave is of the order of

Updated On: Mar 30, 2025
  • 108 ms-1
  • 10-5 ms-1
  • 105 ms-1
  • 10-8 ms-1
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The Correct Option is A

Solution and Explanation

Concept: 

For an electromagnetic wave, the ratio of the magnitudes of electric field (\( E \)) and magnetic field (\( B \)) is equal to the speed of light (\( c \)):

\[ \frac{E}{B} = c \]

Calculation:

The speed of electromagnetic waves (speed of light) in vacuum is approximately:

\[ c = 3 \times 10^{8}\,ms^{-1} \]

Given options are approximate orders of magnitude. The correct closest magnitude from the given choices is:

\[ 10^{8}\,ms^{-1} \]

Final Conclusion:
The ratio of electric field to magnetic field for electromagnetic waves is of the order \( 10^{8}\,ms^{-1} \).

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