Question:
The ratio of resolving powers of an optical microscope for two wavelengths $\lambda_1 = 4000 \mathring A$ and $\lambda_2 = 6000 \mathring A$ is :
The ratio of resolving powers of an optical microscope for two wavelengths $\lambda_1 = 4000 \mathring A$ and $\lambda_2 = 6000 \mathring A$ is :
Updated On: Jul 18, 2024
- 9 : 4
- 3 : 2
- 16 : 81
- 8 : 27
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The Correct Option is B
Solution and Explanation
Resolving power $\propto \frac{1}{\lambda}$
$\frac{RP_1}{RP_2} = \frac{\lambda_2}{\lambda_2}$
$= \frac{6000 \mathring A}{4000 \mathring A}$
$= \frac{3}{2} $
$\frac{RP_1}{RP_2} = \frac{\lambda_2}{\lambda_2}$
$= \frac{6000 \mathring A}{4000 \mathring A}$
$= \frac{3}{2} $
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Concepts Used:
Single Slit Diffraction
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Read More: Difference Between Diffraction and Interference
Central Maximum
